Question 10(Multiple Choice Worth 1 points)
(8.01 MC)

Two lines, A and B, are represented by the equations given below:

Line A: y = x βˆ’ 6
Line B: y = 3x + 4

Which of the following shows the solution to the system of equations and explains why?

(βˆ’5, βˆ’11), because the point satisfies both equations
(βˆ’5, βˆ’11), because the point does not lie on any axis
(βˆ’3, βˆ’5), because the point satisfies one of the equations
(βˆ’3, βˆ’5), because the point lies between the two axes

Respuesta :

we are given

Line A: y = x βˆ’ 6

Line B: y = 3x + 4

so, we can solve it

we can set them equal

and then we can solve for x

[tex] y=x-6=3x+4 [/tex]

now, we can solve for x

[tex] -2x=10 [/tex]

[tex] x=-5 [/tex]

now, we can find y

[tex] y=-5-6 [/tex]

[tex] y=-11 [/tex]

so, we will get intersection points as

(x,y)=(-5,-11)

so, option-A........Answer

y = x βˆ’ 6

y = 3x + 4

y is isolated in both equations, thus, you can set x - 6 and 3x + 4 equal to each other to solve for x.

x - 6 = 3x + 4

-2x - 6 = 4

-2x = 10

x = -5

Substitute -5 for x into either of the original equations to find y.

y = x - 6

y = -5 - 6

y = -11

Plug both x- and y-values into each original equation to check whether these values satisfy both equations.

y = x - 6 --> -11 = -5 - 6 --> -11 = -11 --> True

y = 3x + 4 --> -11 = 3(-5) + 4 --> -11 = -15 + 4 --> -11 = -11 --> True

Answer:

(βˆ’5, βˆ’11), because the point satisfies both equations.