Answer:
The type of interference the person perceives is a Constructive Interference
Explanation:
Before we solve the problem we need to clarify some concepts: Â
There are two types of Interference, the Constructive and the Destructive interference Â
The Constructive Interference happens if the difference between the waves movement is equal to an even semi-wavelength number
The Destructive Interference is the opposite than the Constructive Interference, it happens if the difference between the waves movement is equal to an odd semi-wavelength number
Taking the above into account let´s proceed to solve the problem.
First, we will need to find how much the wavelength is (we will call it l), we know the frequency f=200Hz, we also know the speed of sound is v=330m/s. We will use the next equation:
[tex]l=v/f[/tex] then we get that [tex]l=1.65m[/tex]
In order to find the semi-wavelength we must divide by 2 the previous result, in this case the semi-wavelength will be: Â
[tex]l/2=0.825m[/tex]
Now, we find the difference between the waves movement, which is the difference between both distances, this difference will be called d and we will find it this way:
[tex]d=4.95m-1.65m[/tex] then d=3.3m
After this, we will do a relation between the distance and the semi-wavelength in order to find what type of interference the person perceives, this way:
[tex](d)/(l/2)[/tex] then, we have a relation equals to 4. As it´s an even number, we determine the interference is a Constructive Interference
The person would experience a Constructive Interference.
A constructive interference is a situation where the resultant wave felt is bigger than either of the two original.
Now, Â the difference between the waves movement, which is the difference between both distances, assuming we take d as the difference, we have
4.95m - 1.65m = 3.30m. This would serve as the constructive interference.
Learn more about Constructive Interference here:
brainly.com/question/2166481
