Answer:
 A.  x² +y² -6x -16y +48 = 0
Step-by-step explanation:
The standard-form equation for a circle centered at (h, k) with radius r is ...
  (x -h)² +(y -k)² = r²
For your circle, this is ...
 (x -3)² +(y -8)² = 5²
To put this in general form, you subtract the constant on the right, and eliminate parentheses:
 x² -6x +9 +y² -16x +64 -25 = 0
 x² +y² -6x -16y +48 = 0 . . . . . rearrange to descending powers of x, y
