Answer:
1. C—N Bond of 1, C≡N Bond order 3, C=N Bond Order 2
(least BDE) C—N < C=N < C≡N (Most BDE)
2. Br
  C
  P
  Be
3. Â (least polar) O-F, C-F, Be-F (Most polar)
  (Least) Br-Cl, C-Cl, Be-Cl (Most)
  (least)C-H, C-Cl, C-O (most)
Explanation:
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