1) The horizontal range of the laptop is 75.0 m
2) The initial vertical component of the velocity is 14.7 m/s
Explanation:
1)
The motion of the laptopin this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions: Â
- A uniform motion (constant velocity) along the horizontal direction Â
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction Â
To find the horizontal range of the laptop, we just need to analyze its horizontal motion.
We know that:
- The laptop moves horizontally with a constant velocity of [tex]v_x = 25 m/s[/tex]
- The time of flight of the laptop is [tex]t=3.00 s[/tex]
So, the horizontal range of the laptop is given by
[tex]d=v_x t = (25)(3.00)=75.0 m[/tex]
2)
The total time of flight of a projectile is given by
[tex]t=\frac{2u_y}{g}[/tex]
where
[tex]u_y[/tex] is the initial vertical component of hte velocity
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Here we know that the time of flight is
[tex]t=3.00 s[/tex]
Therefore, we can solve the formula for [tex]u_y[/tex], to find the initial vertical velocity:
[tex]u_y = \frac{tg}{2}=\frac{(3.00)(9.8)}{2}=14.7 m/s[/tex]
Learn more about projectile motion:
brainly.com/question/8751410
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