Answer:
    (M_f)p = -24 i + 24 j + 8 k
Explanation:
Given:
              F = 2 i + 4 j - 6 k
Find:
- Moment of the force F about point P. Â (M_f)p
Solution:
Step 1: Compute vec(PA)
              vec (P) = -2 i - 3 j + 2 k
               vec (A) = 3 i + 3 j - 1 k
Hence, Â Â Â Â Â Â Â Â vec (PA) = vec(A) - vec(P)
              vec (PA) = (3 i + 3 j - 1 k) - (-2 i - 3 j + 2 k)
              vec (PA) = 5 i + 6 j - 3 k
Step 2: Compute (M_f)p
              (M_f)p = vec (PA) x F
              [tex](M_f)_p = \left[\begin{array}{ccc}i&j&k\\5&6&-3\\2&4&-6\end{array}\right] = \left[\begin{array}{c}-24\\24\\8\end{array}\right][/tex]
Hence, Â Â Â Â Â Â Â Â
              (M_f)p = -24 i + 24 j + 8 k
        Â