A rectangular public park has an area of 3,600 square feet. It is surrounded on three sides by a chain link fence. If the entire length of the fence measures 180 feet, how many feet long could the unfenced side of the rectangular park be?

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ranikashyab066 ranikashyab066 · Answer 1 · 2020-03-09T07:25:09+01:00

Answer:

If length of the field is 30 ft, then width is 120 ft.

If the length of the field is 60 ft, then width is 60 ft.

Step-by-step explanation:

Let us assume the length of the rectangular park = L ft

Let us assume the breadth of the rectangular park = B ft

Now, AREA of the given park = L x B

⇒ L x B = 3,600 sq ft ... (1)

Also, the perimeter of three sides = 180 ft

⇒ 2 L + B = 180 ..... (2)

Now, from (1) and (2), we get:

L x B = 3,600

2 L + B = 180 ⇒ B = 180 - 2 L

Substitute this in(1) , we get:

L x B = 3,600 ⇒ L x (180 - 2 L) = 3600

[tex]\implies 180 L - 2L^2 = 3600\\\implies L^2 -90L + 1800 = 0\\\implies (L-30)(L-60)= 0[/tex]

⇒ L = 30 or L = 60

So, if L = 30 ft , then B = 180 - 2L = 180 - 60 = 120 ft

So, if L = 60 ft , then B = 180 - 2L = 180 - 120 = 60 ft

So, if length of the field is 30 ft, then width is 120 ft.

And if the length of the field is 60 ft, then width is 60 ft.