Answer:
Explanation:
From the question we are told that
 The  height is  [tex]h  =  0.518 \  m[/tex]
  The  sphere density is  [tex]\rho =  22.2g/cm^3 =  \frac{22.2 }{1000}  *  1*10^{6} =  22200 kg/m^3[/tex]
  The  radius is  [tex]r =  2.12 \  mm =0.00212 \ m[/tex]
Generally the power required  is mathematically represented as
  [tex]P  =  \frac{16 *  \pi *  \rho *  r *  g *  h^2 * c }{3}[/tex]
substituting values Â
  [tex]P  =  \frac{16 * 3.142 *  22200 *  0.00212 *  9.8 *  0.518^2 *  3.0*10^{8}}{ 3}[/tex]
  [tex]P  = 6.22*10^{11} \  W[/tex]
