Answer: 6.302 â‹… 10^7 kg
Step-by-step explanation:
Subtract the mass of freight train from the mass of the aircraft carrier:
(7.3 â‹… 10^7) - (9.98 â‹… 10^6)
Get both to have the same exponent (6) by moving the decimal on 73:
(73 â‹… 10^6) - (9.98 â‹… 10^6)
Subtract the leading numbers:
(73-9.98) â‹… 10^6 = 63.02 â‹… 10^6
Move the decimal back so the answer is in scientific notation:
6.302 â‹… 10^7 kg
