1. Graham is hiking at an altitude of 14,040 feet
and is descending 50 feet each minute. Max is
hiking at an altitude of 12,500 feet and is
ascending 20 feet each minute. How many
minutes will it take Graham and Max to meet at
the same altitude ?
a. Equation:
1
2
. Solution:
2. At what altitude will Graham and Max meet?
3

Equation 2 to find the altitude: A₁ - r₁t = A₂ + r₂t A₁ and r₁ are Grahams initial altitude and rate. Use given rates, calculated time and solve for A.

A₂ and r₂ are Max's initial altitude and rate.

They will meet in 22 minutes

They will meet at 12940 ft altitude

Step-by-step explanation: Their original heights plus/minus the altitude change per minute (rate) and the time will be equal when they meet.

14040 - 50t = 12500 + 20t subtract 12500 from both sides; add 50t to both sides.

14040-12500 = 20t + 50t

1540 = 70x

22 = t They will meet in 22 minutes.

To get the altitude where they meet, Multiply the time by the rate for each climber. Add or subtract per equation: A₁ - r₁t = A₂ + r₂t

14040 - 22(50) = 12500 + 22(20)

Graham: 22 min × 50ft/min = 1100 ft

Subtract from his starting altitude:

14040 - 1100 = 12940 ft

Max: 22 min ×20 ft/min = 440 ft

Add to his starting altitude

12500 + 440 = 12940 ft

tiare707 tiare707 · Answer 2 · 2021-03-11T01:55:43+01:00

tiare707 tiare707

11-03-2021

Answer:

Answer:

M=22, hope this helps

Step-by-step explanation:

Set up Graham's altitude function A(m):

A(m) = 14040 - 50m <-- we subtract for descending

Set up Max's altitude function A(m):

A(m) = 12500 + 20m <-- we add for ascending

Set the altitudes equal to each other to solve for m:

14040 - 50m = 12500 + 20m

We type this equation into our search engine to solve for m and we get:

m = 22

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