Taking into account the reaction stoichiometry, 1.25 grams of Hâ‚‚ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
In first place, the balanced reaction is:
Mg + 2 HCl  → MgCl₂ + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The following rule of three can be applied: if by reaction stoichiometry 2 moles of Mg form 1 mole of Hâ‚‚, 2.5 moles of Mg form how many moles of Hâ‚‚?
[tex]moles of H_{2} =\frac{2.5 moles of Mgx1 mole of H_{2} }{2 moles of Mg}[/tex]
moles of Hâ‚‚= 1.25 moles
Finally, 1.25 grams of Hâ‚‚ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
Learn more about the reaction stoichiometry:
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