v high - speed stroboscopic photographs show that the head of a 2.00 3 102 - g golf club is traveling at 55.0 m/s just before it strikes a 46.0 - g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40.0 m/s. find the speed of the golf ball just after impact.

Momentum seem to be directly dependent on the value of mass as well as velocity of the object in the direction of motion. it is quantified by "mass velocity". Since mass is a scalar quantity but velocity is a vector, momentum is a vector quantity.

From the given information-

mass of golf club = 200 g

mass golf ball = 46 g

velocity of club before collision = 55 m/s

velocity club after collision =40 m/s

velocity of golf ball before collision = 0 m/s

You need to use conservation of momentum here.

momentum = mass x velocity

Prior to impact, the golf club has a momentum of 0.200 kg * 55 m/s = 11.00 kg m/s.

The ball's not moving before impact, so it has a momentum of zero. Therefore the total momentum before impact will be 11.00 kg m/s. Conservation of momentum dictates the total momentum of the two objects after impact will also be 11.00 kg m/s.

We know the speed of the club after the impact, so the momentum of the club after impqact is 0.200 kg * 40 m/s =8 kg m/s.

So the momentum of the ball must be 11.00 kg m/s - 8 kg m/s = 3 kg m/s, and dividing by the mass of the ball (0.046 kg) gives the speed of the ball, 65.217 m/s

Velocity of golf ball after collision wit golf club is 65.21 m/s

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