Two cities are 2000 km apart and lie on the same north-south line. the latitude of the northernmost city is 52 Degrees N. what is the latitude of the other city? the radius of the earth is approx 6400km

(Do not round until the final answer. Then round to the nearest integer as needed)

Respuesta :

Answer:

Step-by-step explanation:

To solve this problem, we can use the concept of spherical geometry.

Given:

Β  Β The distance between the two cities along the same north-south line is 2000 km.

Β  Β The latitude of the northernmost city is 52 degrees N.

Β  Β The radius of the Earth is approximately 6400 km.

Let's denote:

Β  Β dd as the distance along the surface of the Earth between the two cities.

Β  Β ΞΈΞΈ as the angle formed at the center of the Earth between the two cities.

Β  Β RR as the radius of the Earth.

Β  Β Ο•1Ο•1​ and Ο•2Ο•2​ as the latitudes of the northernmost city and the other city, respectively.

We can use the formula for arc length on a sphere:

d=Rβ‹…ΞΈd=Rβ‹…ΞΈ

We know that the angle ΞΈΞΈ is related to the difference in latitudes between the two cities. Since the cities lie on the same north-south line, the angle ΞΈΞΈ is the difference in latitude between the two cities.

Given that the difference in latitude between the cities is 52βˆ˜βˆ’Ο•252βˆ˜βˆ’Ο•2​, we need to convert this to radians:

ΞΈ=52βˆ˜βˆ’Ο•2180βˆ˜β‹…Ο€ΞΈ=180∘52βˆ˜βˆ’Ο•2​​⋅π

We also know that d=2000d=2000 km and R=6400R=6400 km.

Therefore, we have:

2000=6400β‹…52βˆ˜βˆ’Ο•2180βˆ˜β‹…Ο€2000=6400β‹…180∘52βˆ˜βˆ’Ο•2​​⋅π

Now, we can solve for Ο•2Ο•2​:

20006400β‹…Ο€=52βˆ˜βˆ’Ο•2180∘6400β‹…Ο€2000​=180∘52βˆ˜βˆ’Ο•2​​

13.2β‹…Ο€=52βˆ˜βˆ’Ο•2180∘3.2β‹…Ο€1​=180∘52βˆ˜βˆ’Ο•2​​

13.2β‹…Ο€=52βˆ’Ο•21803.2β‹…Ο€1​=18052βˆ’Ο•2​​

To solve for Ο•2Ο•2​, we can cross multiply:

180=(52βˆ’Ο•2)β‹…(3.2β‹…Ο€)180=(52βˆ’Ο•2​)β‹…(3.2β‹…Ο€)

180=52β‹…(3.2β‹…Ο€)βˆ’Ο•2β‹…(3.2β‹…Ο€)180=52β‹…(3.2β‹…Ο€)βˆ’Ο•2​⋅(3.2β‹…Ο€)

Ο•2β‹…(3.2β‹…Ο€)=52β‹…(3.2β‹…Ο€)βˆ’180Ο•2​⋅(3.2β‹…Ο€)=52β‹…(3.2β‹…Ο€)βˆ’180

Ο•2=52β‹…(3.2β‹…Ο€)βˆ’1803.2⋅πϕ2​=3.2β‹…Ο€52β‹…(3.2β‹…Ο€)βˆ’180​

Now, we can calculate Ο•2Ο•2​:

Ο•2=52β‹…3.2β‹…Ο€βˆ’1803.2⋅πϕ2​=3.2β‹…Ο€52β‹…3.2β‹…Ο€βˆ’180​

Ο•2=166.4Ο€βˆ’1803.2πϕ2​=3.2Ο€166.4Ο€βˆ’180​

Ο•2=166.4Ο€3.2Ο€βˆ’1803.2πϕ2​=3.2Ο€166.4Ο€β€‹βˆ’3.2Ο€180​

Ο•2=52βˆ’1803.2πϕ2​=52βˆ’3.2Ο€180​

Ο•2β‰ˆ52βˆ’18010.08Ο•2β€‹β‰ˆ52βˆ’10.08180​

Ο•2β‰ˆ52βˆ’17.857Ο•2β€‹β‰ˆ52βˆ’17.857

Ο•2β‰ˆ34.143Ο•2β€‹β‰ˆ34.143

Rounding to the nearest integer, the latitude of the other city is approximately 34∘34∘ N.