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Find the center and the radius of the circle x2 + y2 + 6x โˆ’ 4y โˆ’ 23 = 0.
Center: (โˆ’3, โˆ’2), radius: 6
Center: (โˆ’3, 2), radius: square root of six end square root
Center: (โˆ’3, 2), radius: 6
Center: (3, 2), radius: square root of six end square root

Respuesta :

jiggly400

Answer:

C

Step-by-step explanation:

It can be written as,

(x+3)^2 +(y-2)^2-23-9-4=0

โžก๏ธ (x+3)^2 +(y-2)^2=36

โžก๏ธ (x+3)^2 +(y-2) ^2=6^2

Thus,

Centre =(-3,2)

Radius =6 units

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